Optimal. Leaf size=221 \[ \frac{2 \left (a^2 B+2 a A b+3 b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}+\frac{2 \left (3 a^2 A+5 b (2 a B+A b)\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}-\frac{2 \left (3 a^2 A+5 b (2 a B+A b)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 a (5 a B+7 A b) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{15 d}+\frac{2 a A \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a \sec (c+d x)+b)}{5 d} \]
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Rubi [A] time = 0.379852, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.242, Rules used = {2960, 4026, 4047, 3768, 3771, 2639, 4046, 2641} \[ \frac{2 \left (a^2 B+2 a A b+3 b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}+\frac{2 \left (3 a^2 A+5 b (2 a B+A b)\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}-\frac{2 \left (3 a^2 A+5 b (2 a B+A b)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 a (5 a B+7 A b) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{15 d}+\frac{2 a A \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a \sec (c+d x)+b)}{5 d} \]
Antiderivative was successfully verified.
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Rule 2960
Rule 4026
Rule 4047
Rule 3768
Rule 3771
Rule 2639
Rule 4046
Rule 2641
Rubi steps
\begin{align*} \int (a+b \cos (c+d x))^2 (A+B \cos (c+d x)) \sec ^{\frac{7}{2}}(c+d x) \, dx &=\int \sqrt{\sec (c+d x)} (b+a \sec (c+d x))^2 (B+A \sec (c+d x)) \, dx\\ &=\frac{2 a A \sec ^{\frac{3}{2}}(c+d x) (b+a \sec (c+d x)) \sin (c+d x)}{5 d}+\frac{2}{5} \int \sqrt{\sec (c+d x)} \left (\frac{1}{2} b (a A+5 b B)+\frac{1}{2} \left (3 a^2 A+5 b (A b+2 a B)\right ) \sec (c+d x)+\frac{1}{2} a (7 A b+5 a B) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{2 a A \sec ^{\frac{3}{2}}(c+d x) (b+a \sec (c+d x)) \sin (c+d x)}{5 d}+\frac{2}{5} \int \sqrt{\sec (c+d x)} \left (\frac{1}{2} b (a A+5 b B)+\frac{1}{2} a (7 A b+5 a B) \sec ^2(c+d x)\right ) \, dx+\frac{1}{5} \left (3 a^2 A+5 b (A b+2 a B)\right ) \int \sec ^{\frac{3}{2}}(c+d x) \, dx\\ &=\frac{2 \left (3 a^2 A+5 b (A b+2 a B)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 a (7 A b+5 a B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{15 d}+\frac{2 a A \sec ^{\frac{3}{2}}(c+d x) (b+a \sec (c+d x)) \sin (c+d x)}{5 d}+\frac{1}{3} \left (2 a A b+a^2 B+3 b^2 B\right ) \int \sqrt{\sec (c+d x)} \, dx+\frac{1}{5} \left (-3 a^2 A-5 b (A b+2 a B)\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx\\ &=\frac{2 \left (3 a^2 A+5 b (A b+2 a B)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 a (7 A b+5 a B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{15 d}+\frac{2 a A \sec ^{\frac{3}{2}}(c+d x) (b+a \sec (c+d x)) \sin (c+d x)}{5 d}+\frac{1}{3} \left (\left (2 a A b+a^2 B+3 b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx+\frac{1}{5} \left (\left (-3 a^2 A-5 b (A b+2 a B)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx\\ &=-\frac{2 \left (3 a^2 A+5 b (A b+2 a B)\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{5 d}+\frac{2 \left (2 a A b+a^2 B+3 b^2 B\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{3 d}+\frac{2 \left (3 a^2 A+5 b (A b+2 a B)\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 a (7 A b+5 a B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{15 d}+\frac{2 a A \sec ^{\frac{3}{2}}(c+d x) (b+a \sec (c+d x)) \sin (c+d x)}{5 d}\\ \end{align*}
Mathematica [A] time = 2.36768, size = 171, normalized size = 0.77 \[ \frac{\sec ^{\frac{5}{2}}(c+d x) \left (20 \left (a^2 B+2 a A b+3 b^2 B\right ) \cos ^{\frac{5}{2}}(c+d x) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )-12 \left (3 a^2 A+10 a b B+5 A b^2\right ) \cos ^{\frac{5}{2}}(c+d x) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+2 \sin (c+d x) \left (3 \left (3 a^2 A+10 a b B+5 A b^2\right ) \cos (2 (c+d x))+15 \left (a^2 A+2 a b B+A b^2\right )+10 a (a B+2 A b) \cos (c+d x)\right )\right )}{30 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 10.918, size = 750, normalized size = 3.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{2} \sec \left (d x + c\right )^{\frac{7}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (B b^{2} \cos \left (d x + c\right )^{3} + A a^{2} +{\left (2 \, B a b + A b^{2}\right )} \cos \left (d x + c\right )^{2} +{\left (B a^{2} + 2 \, A a b\right )} \cos \left (d x + c\right )\right )} \sec \left (d x + c\right )^{\frac{7}{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{2} \sec \left (d x + c\right )^{\frac{7}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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